Answer
$p(2)=.3456$
Work Step by Step
$p=1-p=1-.4=.6$
$p(x)=\begin{pmatrix} n\\x\end{pmatrix}p^xq^{n-x}$
$p(2)=\begin{pmatrix} 4\\2\end{pmatrix}(.6)^2(.4)^{4-2}=\frac{4!}{2!(4-2)!}(.36)(.4)^2=\frac{4(3)(2!)}{2(2!)}(.36)(.16)=6(.36)(.16)=.3456$
Statistics (12th Edition)
by McClave, James T.; Sincich, Terry T.
Published by
Pearson
ISBN 10:
0321755936
ISBN 13:
978-0-32175-593-3
Chapter 4 - Discrete Random Variables - Exercises 4.50 - 4.76 - Learning the Mechanics - Page 205: 4.55b
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