Answer
a. From the given normal distribution, μ=95 and σ= 20.
For x =130 : z = $\frac{130-95}{20}$ = 1.75
$P(x \gt 130)$ = $P(z \gt 1.75 )$ = .0.0401 approximately.
=4.01%
Work Step by Step
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Introductory Statistics 9th Edition
by Mann, Prem S.
Published by
Wiley
ISBN 10:
1-11905-571-7
ISBN 13:
978-1-11905-571-6
Chapter 6 - Section 6.3 - Applications of the Normal Distribution - Exercises - Page 252: 6.30
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