Answer
From the given normal distribution, μ=3.0 and σ= 0.009.
$P(2.98 \lt x \lt 3.02)$ = $P(\frac{2.98-3.0}{0.009} \lt z \lt \frac{2.98-3.0}{0.009})$
= $P(-2.22 \lt z \lt 2.22)$
= 0. 9869 - 0.0131
=0.9738
=97.38%
Work Step by Step
See above.
Introductory Statistics 9th Edition
by Mann, Prem S.
Published by
Wiley
ISBN 10:
1-11905-571-7
ISBN 13:
978-1-11905-571-6
Chapter 6 - Section 6.3 - Applications of the Normal Distribution - Exercises - Page 252: 6.34
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