Answer
From the given normal distribution, μ=5.75 and σ= 0.11
Probability that pucks produced by a factory can be used=
$P(5.5 \lt x \lt 6)$ = $P(\frac{5.5-5.75}{0.11} \lt z \lt \frac{6-5.75}{0.11})$
= $P(-2.2727 \lt z \lt 2.2727)$
= 0. 9885 - 0.0115
=0.977
Probability that pucks produced by a factory cannot be used=
1 -Probability that pucks produced by a factory can be used=
1-0.977 = 0.023 = 2.3%
Work Step by Step
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