Answer
a. From the given normal distribution, μ=19800 and σ= 350.
$P(x \lt 19445)$ = $P(z \lt \frac{19445-19800}{350})$
= $P(z \lt -1.0143)$
=.1552 approximately.
=15.52%
b. $P(x \gt 20300)$ = $P(z \gt \frac{20300-19800}{350})$
= $P(z \gt 1.4286)$
=.0766 approximately.
=7.66%
Work Step by Step
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