Answer
a. From the given normal distribution, μ=1650 and σ= 320.
For x =1950 : z = $\frac{1950-1650}{320}$ = 0.9375
$P(x \lt 1950)$ = $P(z \lt 0.9375 )$ = .9332 approximately.
b. For x =900 : z = $\frac{900-1650}{320}$ = -0.2.3438
For x =1300: z = $\frac{1300-1650}{320}$ = -1.0938
$P(900 \leq x \leq 1300)$ = $P(1\leq z \leq 2.75)$ = 0.137-0.0095 = .1275 approximately.
= 12.75%
Work Step by Step
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