Answer
$36.86^{\circ} E$ or, $N 53.14^{\circ} E$
Work Step by Step
Let us consider that $v_1=$ Velocity of the swimmer and $v_2=$ Velocity of the river.
Let $R$ be the true or resultant velocity of the swimmer.
Thus, we have
$R=v_1+v_2$
Then $R=2 \cos \theta i+(2 \sin \theta -1.2)j$
Here, the vertical component becomes zero because the swimmer should move horizontally to reach at east point.
Then
$2 \sin \theta -1.2=0$
This implies that
$\sin \theta =\dfrac{1.2}{2}=0.6 \implies \theta =36.86^{\circ} E$ or, $N 53.14^{\circ} E$
