Answer
Magnitude= 2
Direction = 60° (from positive x-axis)
Work Step by Step
$|\vec{v}|= \sqrt (1^{2}+\sqrt 3^{2})$= 2
Considering θ as the angle made by the vector with positive x-axis, we have
tan θ= $\frac{\sqrt 3}{1}$
Or θ=$ tan^{-1} \sqrt 3 $= 60°
