Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 9 - Section 9.1 - Vectors in Two Dimensions - 9.1 Exercises - Page 638: 53

Answer

$F=25.98 i+15 j$

Work Step by Step

The component form of the force $F$ can be determined as: $F=|F| \cos \theta i+|F| \sin \theta j$ The horizontal component of the force $F$ can be determined as: $F_H=|F| \cos \theta i$ and The vertical component of the force $F$ can be determined as: $F_v=|F| \sin \theta j$ Given: $F=30 lb$ Thus, we have $F_H=|F| \cos \theta i=30 \cos 30^{\circ}=25.98 lb$ and $F_v=|F| \sin \theta j=30 \sin 30^{\circ}=15 lb$ Hence, the component form of the force $F$ can be determined as: $F=25.98 i+15 j$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.