Answer
$v=171 i+469.8 j$
Work Step by Step
The component form of the velocity $v$ can be determined as: $v=|v| \cos \theta i+|v| \sin \theta j$
The east component of the velocity $v$ can be determined as: $v_e=|v| \cos \theta i$
and
The north component of the velocity $v$ can be determined as: $v_n=|v| \sin \theta j$
Given: $\theta=20^{\circ}$
Thus, we have
$v_e=|v| \cos \theta i=500 \cos 20^{\circ}=171$mi/h and
$v_n=|v| \sin \theta j=500 \sin 20^{\circ}=469.8$mi/h
Hence, the component form of the velocity $v$ can be determined as: $v=171 i+469.8 j$
