Answer
Q
Work Step by Step
This problem has many parts but the motive is to reduce the theta part to somewhere between $[-2\pi,2\pi]$. To do this we can add or subtract $2\pi$ since that is a complete rotation. So here, $-\pi/4$ and -4. So $-\pi/4$ is on the segment QS since if we rotate $\pi/4$ radians on the unit circle we get to the point S. And -4 is negative so we flip over the center. So Q is the answer.