Answer
$(1, \frac{\pi}{6}) (-1, \frac{19\pi}{6})$
See graph below.
Work Step by Step
7π/6 is in the third quadrant, but since r = -1, then the point will be plotted for $\frac{\pi}{6}$ with a radius of 1
See the graph below.
For different polar coordinates, it can be accomplished by the following:
$(−r,θ+π)=(1,\frac{7\pi}{6}+π)=(1, \frac{\pi}{6})$
or
$(r,θ+2π)=(-1,\frac{7\pi}{6}+ 2π)=(-1, \frac{19\pi}{6})$
