Answer
$(2, \frac{2\pi}{3}) (-2, \frac{5\pi}{3})$
See graph below.
Work Step by Step
Given $(-2, -\frac{\pi}{3})$
$\frac{-\pi}{3}$ is in the fourth quadrant but since r = -2, then the point will be plotted for the angle + $\pi$, thus at $\frac{2\pi}{3}$ with a radius of 1
See the graph below.
For different polar coordinates, it can be accomplished by the following:
$(−r,θ+π)=(2,-\frac{\pi}{3}+π)=(2, \frac{2\pi}{3})$
or
$(r,θ+2π)=(-2,-\frac{\pi}{3}+ 2π)=(-2, \frac{5\pi}{3})$
