Answer
please see image:
Work Step by Step
Draw the terminal side of the angle $-\displaystyle \frac{17\pi}{6}$ in standard position.
This is one $\displaystyle \frac{\pi}{6}$ arc less than $ 3\pi$ from 0, in the clockwise direction.
Terminal side is the same as for $\displaystyle \frac{7\pi}{6}$ (blue, solid line).
$r=-5$ is negative,
so the point P will be opposite the terminal side of the angle (blue dashed),
5 units from the pole (origin).