Answer
a. $4k\pi$
b. $0$
Work Step by Step
a. $\cos\frac{\theta}{2}-1=0$
$\cos\frac{\theta}{2}=1$
$\frac{\theta}{2}=2k\pi$
$\theta=4k\pi$
b. The only value of $\theta$ in $[0, 2\pi)$ is $0$, which occurs when $k=0$ and $\theta=4*0*\pi=0$.
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