Answer
$\theta=\frac{3\pi}{4}$, $\theta=\frac{\pi}{4}$
Work Step by Step
$\cos 2\theta=\cos^2\theta-\frac{1}{2}$
$2\cos^2\theta-1=\cos^2\theta-\frac{1}{2}$
$\cos^2\theta=\frac{1}{2}$
$\cos \theta=\pm\frac{\sqrt{2}}{2}$
If $\cos \theta=\frac{\sqrt{2}}{2}$, then $\theta=\frac{\pi}{4}+k\pi$.
If $\cos \theta=-\frac{\sqrt{2}}{2}$, then $\theta=\frac{3\pi}{4}+k\pi$.