Answer
$0$, $\pi$
Work Step by Step
$\cos x\sin x-\sin x=0$
$\sin x(\cos x-1)=0$
If $\sin x=0$, then the only solutions in $[0, 2\pi)$ are $0$ and $\pi$.
If $\cos x-1=0$, then $\cos x=1$, and the only solution in $[0, 2\pi)$ is $0$.
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 7 - Review - Exercises - Page 578: 31
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