Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Review - Exercises - Page 528: 17

Answer

sin: $\frac{5}{\sqrt 60}$ cos: $\frac{7}{\sqrt 60}$ tan: $\frac{5}{7}$ csc: $\frac{\sqrt 60}{5}$ sec: $\frac{\sqrt 60}{7}$ cot: $\frac{7}{5}$

Work Step by Step

The basic functions are: $sin=\frac{opp}{hyp}$ $cos=\frac{adj}{hyp}$ $tan=\frac{opp}{adj}$ $csc=\frac{hyp}{opp}$ $sec=\frac{hyp}{adj}$ $cot=\frac{adj}{opp}$ Your opposite is 5 (opposite is directly across from the angle). Your adjacent is 7 (adjacent is right next to the angle). To find the missing side, using the pythagorean theorem. $(5^2 + 7^2 = c^2)$/$(74=c^2)$/$(c=\sqrt 74)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.