Answer
(a) $21991$ rad/min
(b) $24435$ rad/min
(c) $254.5$ mi/hr
Work Step by Step
(a) The angular speed of the engine is $\omega_e=3500\times2\pi=7000\pi\approx21991$ rad/min
(b) With a ratio of g= 0.9 the angular speed of the wheels is $\omega_w=\frac{7000\pi}{0.9}\approx24435$ rad/min
(c) With a radius of $r=11in$, the linear speed is $v=r\omega_w\approx268781$ in/min. Using 1mi=63360in and 1hr=60min, we have $v=\frac{268781\times60}{63360}\approx254.5$ mi/hr
