Answer
$AC\approx 1.026;$
$BC\approx 2.819$
$\angle A=90^{0}-\angle B=90^{0}-20^{\circ }=70^{0}$
Work Step by Step
$ ABC$ is a right triangle with a hypothenus $AB=3$
So
$AC=3\sin 20\approx 1.026;BC=3\cos 20\approx 2.819$
And
$\angle A=90^{0}-\angle B=90^{0}-20^{\circ }=70^{0}$
