Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Review - Exercises - Page 528: 28

Answer

The height of the CN Tower is equal to 0.8762 km

Work Step by Step

$base. = 1 \space km$ $base.=1000 m \space\ $\theta = 28.81 ^o $ $$tan \space \theta = \frac{opp.}{adj.}$$ $$opp. = 1 \space km \times tan\space (28.81^o) \approx 0.5499 \space km$$
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