Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Review - Exercises - Page 528: 24

Answer

$a = 40$ $b = 20\sqrt 3$ $\angle C = 30 ^o$

Work Step by Step

Cosine definition: $$cos \space 60^o = \frac{20}{a}$$ $$a = \frac{20 }{cos \space 60 ^o} = \frac{20}{\frac 12} = 40$$ Sine definition: $$sin \space 60^o = \frac{b}{a} = \frac{b}{40}$$ $$b = sin \space 60 ^o \space (40) = \Bigg(\frac{\sqrt 3}{2}\Bigg)(40) = 20 \sqrt 3$$ $$\angle A + \angle B + \angle C = 180 ^o$$ $$\angle C = 180^o - 60 ^o - 90 ^o = 30 ^o$$
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