Answer
Amplitude: 2
Period: $4\pi$
Phase $1/2$
Horizontal shift: $\pi/3$
Work Step by Step
First, one must convert the equation to the following form $y=a\cdot $sin$(k(x-b))$, so it will be $y=2\cdot $sin$(\frac{1}{2}(x-\frac{\pi}{3}))$
Now one can find the data. The amplitude is $|a|$ which is $2$ in this example. The period is found using $\frac{2\pi}{k}$, so $\frac{2\pi}{1/2}=4\pi$. The phase is $k$, which is $1/2$. And the horizontal shift is represented by $b$, which, in this case, is $\pi/3$.
