Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 5 - Review - Test - Page 465: 11

Answer

$y=2$sin$(2(x+\frac{\pi}{3}))$

Work Step by Step

The amplitude is half the distance between the minimum and maximum values of the function. Since the minimum is $-2$ and the maximum is $2$, $\frac{2-(-2)}{2}=2$ The period is the interval needed to complete one cycle, and it is given by $k=\frac{2\pi}{p}$, where $p$ is the period and $k$ is the phase or the horizontal length of a function when it completes one cycle. Since the length, in this case, is $\pi$, $k=\frac{2\pi}{\pi}=2$ Horizontal shift is the amount of units the function has displaced horizontally. Since the sine function starts at the origin, the function has displaced $-\pi/3$
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