Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 5 - Review - Test - Page 465: 14

Answer

$y=5sin(4\pi t)$

Work Step by Step

We translate the word problem into math equations: "2 cycles every second" means the frequency $f=2$, "distance between the highest point and the lowest point" corresponds to twice the oscillating amplitude $2a=10$cm, so $a=5$cm. Use the relationship $\omega=2\pi f=4\pi$, the equation becomes $y=5sin(4\pi t)$
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