Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 5 - Review - Test - Page 465: 6

Answer

Amplitude: 5 Period: $\pi/2$ Phase: 4 Horizontal shift: 0

Work Step by Step

Using the base form $y=a\cdot $cos$(k(x-b))$, one can find the data. The amplitude is $|a|$ which is 5 in this example. The period is found using $\frac{2\pi}{k}$, so $\frac{2\pi}{4}=\pi/2$. The phase is $k$, which is $4$. And the horizontal shift is represented by $b$, which, in this case, is $0$.
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