Answer
$tan(t)=-\frac{sin(t)}{\sqrt {1-sin^2t}}$
Work Step by Step
Since $t$ is in Quadrant II, we know $sint\geq0,cost\lt0$.
By definition, $tant=\frac{sint}{cost}$ and use Pythagorean Identity $cost=-\sqrt {1-sin^2t}$,
we have the answer as $tan(t)=-\frac{sin(t)}{\sqrt {1-sin^2t}}$
