Chapter 3 - Section 3.6 - Rational Functions - 3.6 Exercises - Page 308: 5

$x=-2$ and $x=3$

$r(x) = \frac{(x+1)(x-2)}{(x+2)(x-3)}$ Vertical asymptotes are determined when the denominator is equal to 0 The denominator is conveniently factored, so the denominator is 0 when (x+2) or (x-3) is equal to 0 Thus $x=-2$ and $x=3$