Answer
$y$-intercept: None
$x$-intercept: $3$ and $-3$
Work Step by Step
$r(x)=\dfrac{x^{2}-9}{x^{2}}$
Substitute $r(x)$ by $y$:
$y=\dfrac{x^{2}-9}{x^{2}}$
To find the $y$-intercept, set $x$ equal to $0$ and solve for $y$:
$y=\dfrac{(0)^{2}-9}{(0)^{2}}=\dfrac{-9}{0}$ Undefined
To find the $x$-intercept, set $y$ equal to $0$ and solve for $x$:
$0=\dfrac{x^{2}-9}{x^{2}}$
$(0)(x^{2})=x^{2}-9$
$x^{2}-9=0$
$x^{2}=9$
$\sqrt{x^{2}}=\sqrt{9}$
$x=\pm3$
$y$-intercept: None
$x$-intercept: $3$ and $-3$
