Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Section 3.6 - Rational Functions - 3.6 Exercises - Page 308: 21

Answer

$x$-intercept: $-\dfrac{1}{4}$ $y$-intercept: $1$

Work Step by Step

$r(x)=\dfrac{x-1}{x+4}$ Substitute $f(x)$ by $y$: $y=\dfrac{x-1}{x+4}$ To find the $y$-intercept, set $x$ equal to $0$ and solve for $y$: $y=\dfrac{0-1}{0+4}=\dfrac{-1}{4}=-\dfrac{1}{4}$ To find the $x$-intercept, set $y$ equal to $0$ and solve for $x$: $0=\dfrac{x-1}{x+4}$ $(0)(x+4)=x-1$ $x-1=0$ $x=1$ $x$-intercept: $-\dfrac{1}{4}$ $y$-intercept: $1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.