Answer
$-1, 2$
Work Step by Step
Equating the numerator of the function
$r(x) = \frac{(x+1)(x-2)}{(x+2)(x-3)}$ to zero
we got $(x+1)(x-2)=0$
implies $(x+1)=0$
or $(x-2)=0$
which implies $x= -1$ or $2$
now we can write the following:
the function r has x intercepts $-1$ and $2$
so the required terms are $-1, 2$
