Answer
y-intercept is $\frac{1}{3}$
Work Step by Step
Given $r(x) = \frac{(x+1)(x-2)}{(x+2)(x-3)}$
The y-intercept is when x = 0, so substitute x=0 into r(x)
$r(x) = \frac{(0+1)(0-2)}{0+2)(0-3)}$
$r(x) = \frac{1*-2}{2*-3}$
$r(x) = \frac{1}{3}$
Thus the y-intercept is $\frac{1}{3}$
