# Chapter 2 - Section 2.1 - Functions - Exercises - Page 157: 69

$(4, +\infty)$

#### Work Step by Step

(i) The denominator cannot be equal to zero thus, $\sqrt{x-4}\ne 0 \\x-4 \ne 0^2 \\x-4 \ne 0 \\x \ne 4$ (ii) The radicand (number inside the square root symbol) cannot be negative. Thus, $x- 4 \ge 0 \\x \ge 4$ This means that the value of $x$ has to be greater than four. Therefore, the domain of the function is: $(4, +\infty)$

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