Answer
Net change is 27
Work Step by Step
$h(t) = t^2 + 5$
$h(-3) = (-3)^2 +5 = (9) +5 = 14$
$h(6) = (6)^2 + 5 = (36) + 5 = 41$
$h(6) - h (-3) = 41 - 14 = 27$
Net change is an increase by 27
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 2 - Section 2.1 - Functions - Exercises - Page 157: 42
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