Answer
$$f(x^2) =x^2 +4 $$
$$(f(x))^2 =x^2 + 8x +16 $$
Work Step by Step
For x = $x^2$
$f(x^2) = x^2 +4 $
_______________
$f(x) = x + 4$
therefore
$(f(x))^2 = (x+4)^2$ ... square the polynomial
$=x^2 + 8x +16$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 2 - Section 2.1 - Functions - Exercises - Page 157: 37
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