Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.2 - Arithmetic Sequences - 12.2 Exercises - Page 857: 71


$\$ 1250$.

Work Step by Step

The year-after-year values of the computer form an arithmetic sequence with $a=12,500$ and common difference $d=-1875$. After six years, $\$ 1875$ has been subtracted 6 times, so we are after the term $a_{7}$! $a, a+d, a+2d, a+3d, ... ,a+6d.$ $a_{n}=a+(n-1)d$ $a_{7}=12,500+(7-1)(-1875)=\$ 1250$. The value of the computer after 6 years is $\$ 1250$.
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