## Precalculus: Mathematics for Calculus, 7th Edition

$a_{n}$ = 9 + 4(n-1) 10th term: 45
Use the formula $a_{n}$ = a + d(n-1) and plug in the given values to find a formula for the nth term. For the 10th term, plug in 10 for n and solve: $a_{10}$ = 9+4(10-1) = 9+(4$\times$9) = 36 + 9 = 45.