Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.2 - Arithmetic Sequences - 12.2 Exercises - Page 857: 34

Answer

$d=12$ $a_{n}=\left( -1\right) +\left( n-1\right) \times 12$ $a_{5}=47;$ $a_{100}=1187$

Work Step by Step

$d=a_{n+1}-a_{n}=11-\left( -1\right) =23-11=35-23=12$ $a_{n}=a+\left( n-1\right) d\Rightarrow a_{1}=a+\left( 1-1\right) d=a=-1$ $a_{n}=a+\left( n-1\right) d=\left( -1\right) +\left( n-1\right) \times 12$ $a_{5}=\left( -1\right) +\left( 5-1\right) \times 12=47;a_{100}=\left( -1\right) +\left( 100-1\right) \times 12=1187$
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