## Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole

# Chapter 12 - Section 12.2 - Arithmetic Sequences - 12.2 Exercises - Page 857: 12

#### Answer

$a_{n}$ = -5 + 4(n-1) 10th term: 31

#### Work Step by Step

Use the formula $a_{n}$ = a + d(n-1) and plug in the given values to find a formula for the nth term. For the 10th term, plug in 10 for n and solve: $a_{10}$ = -5 + 4(10-1) = -5 + (4$\times$ 9) = -5 + 36 = 31.

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