Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.2 - Arithmetic Sequences - 12.2 Exercises: 14

Answer

$a_{n}$ = 14 + $\frac{-3}{2}$(n-1) = formula for nth term 10th term: .5

Work Step by Step

Use the formula $a_{n}$ = a + d(n-1) and plug in the given values to find a formula for the nth term. For the 10th term, plug in 10 for n and solve: $a_{10}$ = 14 + $\frac{-3}{2}$(10-1) = 14 + $\frac{-3}{2}$(9) = 14 -13.5 = .5
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