## Precalculus: Mathematics for Calculus, 7th Edition

$a_{n}$ = 14 + $\frac{-3}{2}$(n-1) = formula for nth term 10th term: .5
Use the formula $a_{n}$ = a + d(n-1) and plug in the given values to find a formula for the nth term. For the 10th term, plug in 10 for n and solve: $a_{10}$ = 14 + $\frac{-3}{2}$(10-1) = 14 + $\frac{-3}{2}$(9) = 14 -13.5 = .5