Answer
$r=\dfrac{6}{5+3\sin \theta}$
Work Step by Step
The conversion of polar coordinates and Cartesian coordinates are given as follows:
1. $r^2=x^2+y^2$ or, $r=\sqrt {x^2+y^2}$
2. $\tan \theta =\dfrac{y}{x}$ or,$ \theta =\tan^{-1} (\dfrac{y}{x})$
3. $x=r \cos \theta$ and 4. $y=r \sin \theta$
The equation of conic with eccentricity $e$ and directrix $d=x$ leads to focus can be written as:
$r=\dfrac{de}{1+e \sin \theta}$
Need to multiply the given equation with $\sin \theta$.
Given $e=0.6; d=2$
Thus, $r=\dfrac{1.2}{1+0.6\cos \theta}=\dfrac{6}{5+3\sin \theta}$
