Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 11 - Section 11.6 - Polar Equations of Conics - 11.6 Exercises - Page 829: 7

Answer

$r=\dfrac{20}{1+4\cos \theta}$

Work Step by Step

The conversion of polar coordinates and Cartesian coordinates are given as follows: 1. $r^2=x^2+y^2$ or, $r=\sqrt {x^2+y^2}$ 2. $\tan \theta =\dfrac{y}{x}$ or,$ \theta =\tan^{-1} (\dfrac{y}{x})$ 3. $x=r \cos \theta$ and 4. $y=r \sin \theta$ The equation of conic with eccentricity $e$ and directrix $d=x$ leads to focus can be written as: $r=\dfrac{de}{1+e \cos \theta}$ Need to multiply the given equation with $\cos \theta$. Given $e=4; d=5$ Thus, $r=\dfrac{20}{1+4\cos \theta}$
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