Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 11 - Section 11.6 - Polar Equations of Conics - 11.6 Exercises - Page 829: 14

Answer

$I$

Work Step by Step

The equation of conic with eccentricity $e$ and directrix $d=y$ leads to focus can be written as: $r=\dfrac{d}{1 -\sin \theta}$ when $e=1$ When we look at all the graphs it has been noticed when $e=1$ . This shows that the conic is a parabola, so the correct graph is $I$.
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