Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 11 - Section 11.6 - Polar Equations of Conics - 11.6 Exercises - Page 829: 5

Answer

$\dfrac {2}{1+\sin \theta }$

Work Step by Step

It is Parabola when $e=1$ $r=\dfrac {ed}{1+e\sin \theta }=\dfrac {1\times 2}{1+1\times \sin \theta }=\dfrac {2}{1+\sin \theta }$
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