Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 11 - Section 11.6 - Polar Equations of Conics - 11.6 Exercises - Page 829: 6

Answer

$\dfrac {4}{2-\sin \theta }$

Work Step by Step

Becouse directx is $y=-4$ (negative and paralel to $x$ ) $r=\dfrac {ed}{1-e\sin \theta }=\dfrac {\dfrac {1}{2}\times 4}{1-\dfrac {1}{2}\sin \theta }=\dfrac {4}{2-\sin \theta }$
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