Answer
Hyperbola matches with the graph labeled as IV
Work Step by Step
$y^2-\frac{x^2}{9}=1$
Hyperbola with vertical transverse axis:
$\frac{y^2}{a^2}-\frac{x^2}{b^2}=1$
So:
$a^2=1$
$a=1$
Vertices: $V(0,±a)=V(0,±1)$
Hyperbola matches with the graph labeled as IV
