Answer
See graph and explanations.
Work Step by Step
(a) With the hyperbola $\frac{x^2}{4^2} -\frac{y^2}{3^2}=1 $, we get $c=\sqrt {4^2+3^2}=5$, and the vertices are at $(\pm4,0)$, foci at $(\pm5,0)$, and the asymptotes are $y=\pm\frac{3}{4}x$
(a) With the hyperbola $\frac{y^2}{4^2} -\frac{x^2}{3^2}=1 $, we get $c=\sqrt {4^2+3^2}=5$, and the vertices are at $(0,\pm4)$, foci at $(0,\pm5)$, and the asymptotes are $y=\pm\frac{4}{3}x$
