Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 11 - Section 11.3 - Hyperbolas - 11.3 Exercises - Page 805: 5

Answer

III

Work Step by Step

$\frac{x^{2}}{4}-y^{2}=1$ is in the form $\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1$ which is the standard equation of a hyperbola with x-axis as transverse axis. This implies that graph II and graph IV doesn't match with the given equation. Comparing $\frac{x^{2}}{4}-y^{2}=1$ with $\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1$, we get a=2 a is the distance between the vertex and the center. In graph III, the distance between the center and the vertex is 2. Therefore, graph III is the correct match.
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