Answer
(a) Vertices: $V(0,±1)$
Foci: $F(0,±\sqrt {26})$,
Asymptotes: $y=±\frac{1}{5}x$
(b)
Length of the transverse axis:
$2a=2$
(c)
Work Step by Step
$\frac{y^2}{1}-\frac{x^2}{25}=1$
Hyperbola with vertical transverse axis:
$\frac{y^2}{a^2}-\frac{x^2}{b^2}=1$
$a^2=1$
$a=1$
$b^2=25$
$b=5$
$c^2=a^2+b^2=1+25=26$
$c=\sqrt {26}$
(a) Vertices: $V(0,±a)=V(0,±1)$
Foci: $F(0,±c)=F(0,±\sqrt {26})$,
Asymptotes: $y=±\frac{a}{b}x=±\frac{1}{5}x$
(b)
Length of the transverse axis:
$2a=2$
