Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.4 - The Algebra of Matrices - 10.4 Exercises - Page 721: 22

Answer

$X=\left[\begin{array}{rr} -2 & -7/3\\ 1/3 & 1/3 \end{array}\right]$

Work Step by Step

$ 2A=B-3X\qquad$... add $3X$ to both sides $ 2A+3X=B\qquad$... subtract 2A from both sides $ 3X=B-2A\qquad$... multiply both side with $\displaystyle \frac{1}{3}$ $X=\displaystyle \frac{1}{3}(B-2A)$ $X=\displaystyle \frac{1}{3}(\left[\begin{array}{ll} 2 & 5\\ 3 & 7 \end{array}\right]-2\displaystyle \left[\begin{array}{ll} 4 & 6\\ 1 & 3 \end{array}\right])$ $X=\displaystyle \frac{1}{3}\left[\begin{array}{ll} 2-8 & 5-12\\ 3-2 & 7-6 \end{array}\right]$ $X=\left[\begin{array}{ll} -2 & -7/3\\ 1/3 & 1/3 \end{array}\right]$
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